Can you do this concentration problem?

Question

in a catalytic experiment involving the Harber process, N2 + 3H2 → 2NH3，the rate of reaction was measured as △[NH3]/△t=2.0×10^-4 mol/L×s. What is the rate of reaction expressed in terms of (a)N2, (b) H2.

I am confused with how to express in N2 and H2?

in this case, do I use 2.0×10^-4 mol/L×s=[N2][H2]^3 to find out the answer?

please explain in details, thank you very much!

Answer 1

N2 + 3H2 ----> 2NH3

Use the coefficients of the reaction to help you solve the problem.

(a) In terms on N2

2.0 x 10^-4 mol NH3/Ls * 1mol N2/2mol NH3 = 1.0 * 10^-4 mol N2/Ls

(b) In terms on H2

2.0 x 10^-4 mol NH3/Ls * 3 mol H2/2mol NH3 = 3.0 * 10^-4 mol H2/Ls