Can you guys help me solve this: x²-4x+1=0?

Question

Can you guys help me solve this: x²-4x+1=0?

Answer 1

x²-4x+1=0

x^2 - 2 (x) (2) + 2^2 + [1 - 2^2]= 0 >>> added & subtracted 4

[x - 2]^2 - [root3]^2 =0

[x - 2+ root3] [x-2-root3] =0

x = 2 + root3

x = 2 - root 3

corrected

Answer 2

x²-4x+1=0

=> x²-4x+4=3

=> (x-2)² = 3

=> x-2 = ±√3

=> x = 2±√3.

Answer 3

x = [ 4 ± √ (16 - 4  ) ] / 2

x = [ 4 ± √ (12) ] / 2

x = [ 4 ± 2√3 ] / 2

x =  2 ± √3  

Answer 4

It doesn't factor, so you need to use the quadratic formula.  Look in your book.