Question:

Can you help me graph these parabolas?

by  |  earlier

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My summer packet cut off the instructions telling me how to do this part of the packet. Can you help me find the vertex, axis of symmetry, and x and y intercepts while using the completing the square method:

1. y=x^2-2x-7

2. y=4x^2-8x+2

3. y=1/2x^2+4x+8

4. y=-2x^2-4x+3

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  1. 1. y=x^2-2x-7

    y=(x-1)^2-8

    Vertex (1,-8)

    Axis of symmetry x=1

    y-intercept y=-7

    x-intercept x=1+/-sqrt(8)

    2. y=4x^2-8x+2

    y=4(x-1)^2-2

    Vertex (1,-2)

    Axis of symmetry x=1

    y-intercept y=2

    x-intercept x=1+/-sqrt(1/2)

    3. y=1/2x^2+4x+8

    y=(1/2)(x+4)^2

    Vertex (-4,0)

    Axis of symmetry x=-4

    y-intercept y=8

    x-intercept x=-4

    4. y=-2x^2-4x+3

    y=-2(x+1)^2+5

    Vertex (-1,5)

    Axis of symmetry x=-1

    y-intercept y=3

    x-intercept x=-1+/-sqrt(5/2)

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