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Can you help me with this Co-ordinate Geometry problem?

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The family of straight lines given by, ax+by+c=0 with the condition

6a^2-3b^2-c^2+7ab-ac+4bc=0 meet at the point_____.

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  1. Greetings,

    6a^2-3b^2-c^2+7ab-ac+4bc=0

    (2a + 3b - c)(3a - b + c) = 0

    2a + 3b - c = 0 or 3a - b + c = 0

    -2a - 3b + c = 0 or 3a - b + c = 0

    x = -2, y = -3 or x = 3, y = -1

    Regards

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