Can you please help me figure how to set the equation up.?

Question

Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?

Answer 1

Let d = # of dimes and n = # of nickels.

The number of dimes were doubled. So there would be a 2d in the equation.

The number of nickels were increased by 8, which would make the equation have a (n + 8) in it.

And the value of the coins equal $10.45.

So~

2d+n+8 = 10.45 but that's not the final equation.

U have to make it right by multiplying the value of the coins to it.

So~

0.1(2d) + 0.05(n + 8) = 10.45

And

0.2d + (0.05n + 0.4) = 10.45 for the simplified equation.

And u can solve the equation!

Answer 2

10.54-5.65=4.89

8*.05=.40

4.89-.40=4.49

4.49/.1=44.9

44.9/2=22.5 round to 23 dimes

Answer 3

d = dimes

n = nickels

2d + (n + 8) = $10.45

Answer 4

Joe has a collection of nickels and dimes that is worth $5.65.

1) 5n + 10d = 565

If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45

2) 5(n + 8) + 10(2d) = 1045

Simple two equations in two unknowns

Answer 5

IF n is the number of nickels, and d is the number of dimes, then:

the first equation is;

n*0.05 + d*0.1 = 5.65

The second equation is:

(n+8)*0.05 + 2d*0.1 = 10.45

Now, solve the simultaneous equations.  Let me know if you need help setting up the solution.

Answer 6

.05n + 0.1d = 5.65 where n = some number of nickles and d is dimes (this is the equation for the money value-- not the number of nickels or dimes).

So, if d became 2d  and n became (n+8), it's 10.45.

.05(n+8) + 0.1(2d) = 10.45

Simplify:

0.05n + 0.4 + 0.2d = 10.45

0.05n + 0.2d = 10.05

Solve:

0.05n + 0.2d = 10.05

0.05n + 0.1d = 5.65

Subtract the second equation from the first to get:

0.1d = 4.40

d = 44 dimes

But he has 2d or 88 dimes.

Answer 7

Let N = number of nickels now, D = number of dimes now.

.05N + .10D = 5.65

.05(N+8) + .10(2D) = 10.45

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