Question:

Can you show me how to get the 2nd term or this in this inequality (2x+1)/(x+2)<3?

by  |  earlier

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i get how to get x<-5 but where does x>-2 come from

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  1. (2x+1)/(x+2)&lt;3

    (2x+1)/(x+2) - 3&lt;0

    [(2x+1)-3(x+2)]/(x+2)&lt;0

    now there are two answer

    (2x+1)-3(x+2)&lt;0

    -x-5&lt;0

    x&gt;-5

    or

    (x+2)&lt;0

    x&lt;-2

    so answer is

    -5&lt;x&lt;-2

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