Chem help (pH calculation)?

Question

calculate the pH of a solution prepared by dissolving 0.37 mol of formic acid (HCO2H) and 0.23 mol of sodium formate (NaCO2H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.8x10 -4

Answer 1

1.8e-4 = [H+] [formate] / [formic]

1.8e-4 = [H+] [0.23] / [0.37]

H+ = 2.90e-4

pH = 3.538

your answer is: 3.54