Chemistry Question - Solutions?

Question

Hey guys I know this question is simple, but my answer is just different ot the back of the book.

If 250ml of 2 M HCl is diluted to 1L, what amount of HCl (in mol) is present in 80ml of diluted solution..

I did,

C1V1=C2V2

2 * .25 = c2 * 1

c2 = .5

then ratios

.5/1 = C/.08

C(80mL) = .04

c = n/v , .04 = n/ .08 n = .0032...

the answer is .0075 i dont understand..

Answer 1

Moles HCl = 0.250 L x 2 M = 0.500

concentration of the diluite solution = 0.500 mol / 1 L = 0.500 M

Moles in 80 mL = 0.080 L x 0.500 =0.040

I thing that the answer is wrong

Answer 2

I also agree with Dr.A. The answer in the book seems wrong.

I tried solving it and got the same answer as both of you, and I tried many different approach to try to get 0.0075 but it is never possible, I always get 0.04.