Chemistry: Stoichiometry?

Question

Solve and please show work for 10 pts.

30.5 g of sodium metal reacts with a solution of excess lithium bromide. How many grams of lithium metal are produced?

Answer 1

The balanced reaction is

Na + LiBr ---------> NaBr + Li

Molar mass(mass of 1 mol) of Na = 23 g

Number of moles of Na metal that reacted with excess LiBr = 30.5g/23g = 1.326 mol Na

According to the balanced chemical equation, 1 mol of Na metal produces 1 mol Li metal.

So 1.326 mol Na produces 1.326 mol Li.

Molar mass of Li = 6.941 g

So mass of 1.326 mol Li = 9.20 g Li metal are produced