Question:

Chemistry Stoichiometry with a Twist..confused

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Aspartame has a molecular formula of C14H18N2O5. Find the atoms of nitrogen in 1.2grams of aspartame.

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  1. find the number of molecules in 1.2 garms of aspartame using avadgodro's sumber

    then, use the conversion factor: 1 molecule of aspartame=the number of nitrogen atoms in this molecule (which in this case is 2)

    so,

    # of molecules of aspartame * 2 nitrogen atoms/1 molecule of aspartame

    , will yeild u the # of nitrogen atoms u have

    hope that helped!!


  2. 1.2gAsp * (1 mol asp/ molarmass of asp) * (2 mol nitrogen/1mol asp) * (6.02e23 atoms nitrogen/1 mol nitrogen) = answer

    asp = aspartame

    6.02e23 = 6.02 *10^23

    i'm supposing you know how to find the molar mass right?

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