Chemistry assignment help please?

Question

A student finds that 15.20 g of nitrogen will react with 17.37 g, 34.74 g or 43.43 g of oxygen to form three different compounds. What are the empirical formulas of these three compounds? Please show all the work

Answer 1

Moles N = 15.20 g / 14.0067 g/mol =  1.085

Moles O = 17.37 g / 15.9994 g/mol = 1.085

the ratio is 1 : 1 and the compound is NO

Moles N = 1.085

Moles O = 34.74 g / 15.9994 g/mol = 2.171

1.085 / 1.085 = 1 => N

2.171 / 1.085 = 2 => O

NO2

Moles N = 1.085

moles O = 43.43 g / 15.9994 g/mol =  2.714

1.085 / 1.085 = 1 => N

2.714 / 1.085 = 1.5 => O

to get whole numbers we multiply by 2

N2O3