Chemistry help, can someone show me how to do this?

Question

A 2.00-g sample of a compound gave 4.86-g of CO2 and 2.03-g of H2O on combustion in oxygen. The compound is known to contain only C, H and O. What is its simplest formula?

Answer 1

Moles CO2 = Moles C in the compound = 4.86 g / 44.0098 g/mol =0.110

Mass C = 0.110 mol x 12.011 g/mol =1.32 g

Moles water = 2.03 g / 18.02 g/mol =0.113

Moles H = 2 x 0.113 = 0.226

Mass H = 0.226 mol x 1.008 g/mol =0.228 g

Mass O = 2.00 - ( 1.32 + 0.228)= 0.452 g

Moles O = 0.452 g / 15.9994 g/mol =0.0283

C (0.110) H ( 0.226) O ( 0.0283)

we divide by the smallest number

0.110 / 0.0283 = 4 => C

0.226 / 0.0283 = 8 => H

0.0283 / 0.0283 = 1 => O

C4H8O is the simplest formula