Chemistry help very very urgent?

Question

what volume of solution is required for

0.25 mol/l solution containing 58.5g of sodium chloride

0.1 mol/l solution containing 1.06g of sodium carbonate

0.4 mol/l solution containing 40g of sodium hydroxide

1.25 mol/l solution containing 14.9g of potassium chloride

0.01 mol solution containing 9.1g of potassium nitrate.

please show working if possible. Thank you very much if you can help.

Answer 1

V = moles / molarity

divide the mass of each compound by molar mass to get the moles

Moles NaCl = 58.5 g / 58.4428 g/mol = 1.00

V = 1.00/ 0.25 =4.00 L

Moles Na2CO3 = 1.06 g / 105.99 g/mol =0.0100

V = 0.0100 / 0.1 = 0.100 L

Moles NaOH = 40 / 40 g/mol = 1.0

V = 1.0/ 0.4= 2.5 L

Moles KCl = 14.9 g / 75.553 g/mol =0.200

V = 0.200 / 1.25 =0.160 L

Moles KNO3 = 9.1 g / 101.1 =0.0900

V = 0.0900 / 0.01 =9.00 L