Chemistry problems using density,moles, and volume?

Question

I'm having trouble finding the answer to these. Please help!

Detonation of nitroglycerin:

4C3H5N3O9 yields 12CO2+6N2+O2+H2O (already balanced)

A. If a sample containing 3.00 mL of Nitroglycerin(density=1.592g/mL) is detonated, how many total moles of gas are produced?

B. If each mole of gas occupies 55L under the conditions of the explosion,how many liters of gas are produced?

C.How many grams of N2 are produced in the detonation?

Even if anyone could tell me how to solve these? You don't have to actually solve them if you don't want to, Thanks!

Answer 1

Mass nitroglycerin = 3.00 mL x 1.592 g/mL = 4.776 g

Moles = mass / molar mass = 4.776 g/ 227.0872 g/mol = 0.02103

the ratio between nitroglycerin and Carbon dioxide is 4 : 12

moles CO2 = 0.02103 x 12 / 4 =0.06309

the ratio between nitroglycerin and N2 is 4 : 6

moles N2 = 0.02103 x 6 / 4 =0.03155

the ratio between nitroglycerin and O2 is 4 : 1

moles O2 = 0.02103 x 1 / 4 = 0.005258

the ratio between nitroglycerin and water is 4 : 1

in the same way moles water = 0.005258

total moles = 0.06309 + 0.03155 + 0.005258 + 0.005258 = 0.1052

0.1052 x 55 =  5.78 L

Mass N2 = 0.03155 mol x 28.0134 g/mol = 0.8838 g

Answer 2

download this book on torrent.

i got A for my chem in uni. jus readin this book.

(if you dont know what torrent is..google it)

Brown,LeMay - Chemistry - The Central Science 9e

I'm busy and i cant help you out with the prob.

[download free book on torrent]

good luck

Answer 3

From our chemical equation (recipe):

4C3H5N3O9 yields 12CO2+6N2+O2+H2O

We can see that 4 moles of nitroglycerin yields 6 moles of N2.  Also, if we can determine the mass of nitroglycerine, from the volume and density, then we can convert to moles of nitroglycerin (Molecular weight = 227.0865 g/mol) and then to moles of N2 (Molecular Weight = 28.0 g/mol).  This is shown below:

3.00 mL Nitro * 1.592 g Nitro/mL = 4.776 g of Nitro

4.776 g Nitro * 1mol/227.0865g Nitro = 0.0210 mol Nitro

0.210 mol Nitro * 6 mol N2/4mol Nitro = 0.0315 mol N2

Now to convert to liters of gas:

0.0315 mol N2 * 55L/mol = 1.74 L of N2 gas

Same for other gases, then simply add the volumes.

Now to convert moles of N2 to grams:

0.0315 mol N2 * 28.0 g/mol = 0.882 g of N2 gas

If you just balance the equation, read the equation, and do the stoichiometry, all these problems are very similar!