Chemistry question? Could someone please help!?

Question

An experiment calls for 0.0411 g of potassium hydroxide, KOH. How many milliliters of 0.0154 M KOH are required?

Answer 1

First, determine the number of moles of KOH that you need:

0.0411g/[39.09 + 16.00 + 1.01] = 0.000733 mole

Now set up the equation:

0.0154mol/L x x liters = 0.000733 moles

x liters =  0.000733mole/0.0154mole/liter

x = 0.0476 l

x = 47.6 ml