Chemistry question - electrochemistry

Question

Electrolysis of an alkaline earth metal chloride using a current of 5.00 A for 748 seconds deposits 0.471 g of metal at the cathode. What is the identity of the alkaline earth metal?

Answer 1

X2+ + 2e- >> X

5.00 coulomb/s x 748 s =3740 coulombs

3740 / 96,500 =0.0388 faraday

0.0388 faraday ( 1 mole X/ 2 Faradays) =0.0194 mol

0.471 g / 0.0194 mol =24.3 g/mol

It is Mg