Cn some1 plz help me in ths problem.i wud appreciate?

Question

The solubility of copper(I) chloride is 3.91mg per 100.0L of solution.Calculate Ksp for CuCl.

Answer 1

Let's get the solubility in terms of moles / L.

3.91 mg Cu / 0.100 L x (1 g / 1000 mg) x (1 mole Cu / 63.6 g Cu) = 6.15 x 10^-4 moles / L = 6.15 x 10^-4 M

. . . . . .. . . .CuCl2(s)  =>  Cu2+(aq) + 2Cl-(aq)

Molarity. . .0.000615. . . 0.000615. . 2

(0.000615)

So when 0.000615 M CuCl2 dissolves it produces 0.000615 M Cu2+ and TWICE that amount of Cl-, or 0.00123 M.

Ksp = [Cu2+][Cl-]^2 = (0.000615)(0.00123)^2 = 9.3 x 10^-10