College Physics help please! Thanks?

Question

The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time (in seconds) would be required for the car to accelerate from rest to 53.2 miles per hour? (The car would need rocket boosters!)

_____s

Thanks for any help!!

Answer 1

V2 = V1 + at

24.01 = 0 + 68.6t

24.01 = 68.6t

0.35005669 s = t

Answer 2

well, if g is given as 32.2 ft/s^2 (and it is), then a car designed to go 7g would accelerate at 7 * 32.2 = 225.4 ft/s^2

convert 53.2 mi/hr to ft/s

5280 ft / mi

60 s / min, 60 min / hr = 3600 s / hr

53.2 mi/hr *(5280 ft / mi) / (3600 s / hr) = 78 ft/s

velocity is acceleration times time, and initial velocity is given as 0.

v = at => t = v/a

t = 78/225.4 = .35s