Composition of functions??

Question

g(t) = (t+1)/2, h(t) = (t-3)/4

find g(h(t)).

could you please show working. thanks.

Answer 1

g [ (t - 3) / 4 ]

[ (t - 3)/4 + 1 ] / 2

[ t/4 + 1/4 ] / 2

(t + 1) / 8

Answer 2

g(h(t))=((t-3)/4)+1)/2

=(t-3+4)/8

=(t+1)/8

Answer 3

g(h(t)) =

g(t-3 / 4) = (((t-3)/4) +1)/2

= ((t- 3 +4)/4) / 2

= (t+1)/4))/ 2

= (t+1) / 8

Answer 4

g(t) = (t+1)/2, h(t)=(t-3)/4

g(h(t)) = g (substitute with the value of h(t))

           = g((t-3)/4)

*substitute (t-3)/4 into the equation of g(t)

g(h(t)) = (t+1)/2

          = ((t-3)/4 + 1)/2

          = ((t-3)/4 + 4/4)/2

* equalize the denominators b4 doing the operation

g(h(t)) = ((t-3+4)/4)/2

         = ((t+1)/4)/2

         = (t+1)/4 * 1/2

         = (t+1)/8

hope this helps you...^_^