Compute the voltage. Help me out? Im so confused. ?

Question

Compute the voltage of a cell in which one half-cell is the hydrogen half-cell with hydrogen at a pressure of 203 kPa and 1.00M H+. The other half-cell is Zn and Zn2+ at 1.00M. All other conditions are standard.

Answer 1

If the cell is a voltaic one, then

Zn(s) + 2H+(aq) ==> H2(g) + Zn2+(aq)  Eo = 0.76 V

203 kPa x (1 atm / 101.3 kPa) = 2.00 atm

So Q = (P H2) [Zn2+] / [H+]^2

= (2.00)(1.00) / (1.00)^2 = 2

E cell = Eo - 0.059/n log Q

= 0.76 - 0.059/2 log 2

= 0.76 - 0.01 = 0.75 V