Question:

Confusing gas law question?

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A person accidentally swallows a drop of liquid oxygen which has a density of 1.147g/mL. Assuming the drop has a volume of 0.050mL what volume of gas will be produced in the persons stomach at body temperature (37C) and a pressure or 1 ATM.

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Thanks in advance

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  1. (1.147 g/mL)(0.050 mL)(22.4 L/15.999 g)(310.15°K/293.15°K) ≈ 0.084951 L ≈ 84.95 mL

    but you can't swallow LOX either accidentally or deliberately. Even if it made it as far as your throat, it would freeze your throat shut.

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