Consider the mechanism?

Question

ClO- (aq) + H2O(l) -> HOCl(aq) + OH- (aq) K, fast

I- (aq) + HOCl(aq) -> HOI (aq) + Cl- (aq) k1, slow

HOI (aq) + OH- (aq) -> OI-(aq) + H2O(l) k2, fast

what is the rate law?

A) k1k2K [ClO-] [I-]

B) k1K [ClO-] [I-] [OH-]^-1

C) k1K [ClO-] [I-]

D) k1 [I-] [HOCl]

E) k1K [ClO-] [I-] [OH-]

Answer 1

The answer is C.

That's because the rate is determined by the slowest step.

the second step

if you just went with that mechanism you would have

k1 [HOCl][I-]

however, HOCl is derived by the first step

which has rate law of

K[Clo-] so you need to substitute that in for [HOCl]

which will give you C

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