Consider the reaction 4Fe (s) 3O2 (g) __2Fe2O3(s) if 3.00 mol Fe reacts with the excess O2 how many moles of

Question

Fe2O3 can be produce

Answer 1

If the balanced equation is

4 Fe (s) + 3 O2 (g)  --->  2 Fe2O3 (s)

Then for every mole of Iron, 0.5 moles of Fe2O3 is produced.

3.00 moles * 0.5  = 1.5 moles of Fe2O3.

Answer 2

The balanced equation of the reaction is

4 Fe (s) + 3 O2 (g) -> 2 Fe2O3 (s)

Notice the mole ratio of Fe and Fe2O3. You notice 4 moles of Fe produces only 2 moles of Fe2O3. Therefore, 1 mole of Fe produces 0.5 moles of Fe2O3.

Therefore moles of Fe2O3 is

3.00 moles * 0.5 = 1.5