Constant acceleration: special case problem?

Question

constant acceleration: special case problem?

An electron has a constant acceleration of +3.2 m/s^2. At a certain instant its velocity is +9.6 m/s. What is its velocity(a) 2.5 s earlier and (b) 2.5 s later?

Answer 1

Simply use the equation

V = Vo + A T

where

Vo = Velocity at an initial time

A   = Acceleration

T   = time

to get

(a) 1.6 m/s

(b) 17.6 m/s