Conversion question for math. any ideas? thanks!?

Question

On a new Jekyll temperature scale, water freezes at 17 and boils at 97 . On another new temperature scale, the Hyde scale, water freezes at 0 and boils at 120. If methyl alcohol boils at 84 H, what is its boiling point on the Jekyll scale?

Answer 1

J=(2/3)H+17

J=(2/3)*84+17=73

Answer 2

On the Hyde scale boiling and freezing of water are separated by 120 degrees, and on the Jekyll scale they are separated by 80 degrees, so:

From Hyde to Jekyll:

J = H/120 * 80 + 17

From Jekyll to Hyde:

H = (J - 17) / 80 * 120

Using the first formula, 84H = 84/120 * 80 + 17 = 73J