Question:

Could someone simplify these equations using boolean algebra, thank you?

by  |  earlier

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a) (X + X' .Y) . (X+Y')

b) A' . B' (A+C' )+(B+C)+C

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  1. Greetings,

    (x + x'y)(x + y')

    = xx + xx'y + xy + y'x'y

    = x + 0 + xy + 0

    = x + xy

    = x(1 + y)

    = x(1)

    = x

    a'b'(a + c') + (b + c) + c

    = a'b'a + a'b'c' + b + (c + c)

    = 0 + a'b'c' + b + c

    = a'b'c' + b + c

    Regards

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