Could you help me with these three Algebra questions?

Question

1. Simplify the given equation.

17x - 6 + 3x - 5 = x + 11 + 4x

A) 20x - 11 = 5x + 11

B) 20x + 1 = 5x + 11

C) 9x = 16x

2. Solve for x.

9(x - 2) = 18

A) x = 0

B) x = 16/9

C) x = 20/9

D) x = 4

3. Solve for x.

7(x - 3) = 4(x + 5)

A) x = 1/11

B) x = 1/3

C) x = 41/11

D) x = 41/3

Answer 1

1. a

2. d

3. d

Answer 2

17x - 6 + 3x - 5 = x + 11 + 4x

20x -11= 5x +11 ===> A

15x = 22

x = 22/15

9(x-2)=18

x-2 = 2

x = 2+2=4===> D

7(x - 3) = 4(x + 5)

7x-21 = 4x+20

3x = 41

x = 41/3==>D

Answer 3

what you need to do is combine

1. 20x-11=5x+11

2. a

3. not sure

Answer 4

17x - 6 + 3x - 5 = x + 11 + 4x

20x-11=5x+11

9(x - 2) = 18

9x=36

x=4

7(x - 3) = 4(x + 5)

7x-4x=20+21

3x=41

x=41/3

Answer 5

1. Simplify the given equation.

17x - 6 + 3x - 5 = x + 11 + 4x

Rearrange the terms:

17x + 3x - 6 - 5 = x + 4x + 11

Combine like terms on the left and the right:

20x - 11 = 5x + 11

A) 20x - 11 = 5x + 11

2. Solve for x.

9(x - 2) = 18

Distribute the 9:

9x - 18 = 18

Add 18 to both sides:

9x = 36

Divide by 9:

x = 4

D) x = 4

3. Solve for x.

7(x - 3) = 4(x + 5)

Distribute the 7:

7x - 21 = 4(x + 5)

Distribute the 4:

7x - 21 = 4x + 20

Subtract 4x from both sides:

3x - 21 = 20

Add 21 to both sides:

3x = 41

Divide by 3:

x = 41/3

D) x = 41/3

Answer 6

Number one is A and two is D  

Answer 7

1= A

2=D

dont feel like doing the third. soo good luck witht that one

Answer 8

1. A

2. D