Could you help me with these three math questions?

Question

1. Solve this problem on paper using all four steps.

A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they doubled the sales of the second week for the third week to sell a total of 431 boxes of cookies, how many did they sell each week?

They sold ___ boxes the first week, ___ boxes the second week, and ___ boxes the third week.

2. Solve this problem on paper using all four steps.

Ted weighs twice as much as Julie. Mike weighs three times as much as Julie. Together, Ted, Mike, and Julie weigh 210 lbs. What is the weight of each person?

Julie weighs ___ pounds, Ted weighs ___ pounds, and Mike weighs ___ pounds.

3. Solve this problem on paper using all four steps.

Find four consecutive integers whose sum is 114.

The integers are __, __, __, and ___.

Answer 1

Elektris... Hi !!

A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they doubled the sales of the second week for the third week to sell a total of 431 boxes of cookies, how many did they sell each week?

Identifying the given:

Let B = Boxes of cookies sold at 1st week.

B + 5 = Boxes of cookies sold at 2 nd week.

2(B + 5) = Boxes of cookies sold at 3 rd week.

Sum = 431

B + (B + 5) + 2(B + 5) = 431 ← Making the formula thru the given condition

B + B + 5 + 2B + 10 = 431

4B = 431 -15

4B = 416 ← getting the answer

The answer is Applied to the Condition

B = 104 Boxes Sold on the 1st week

B + 5 = 109 Boxes  Sold on the 2nd week

2(B + 5) = 281  Boxes  Sold on the 3rd week

Ted weighs twice as much as Julie. Mike weighs three times as much as Julie. Together, Ted, Mike, and Julie weigh 210 lbs. What is the weight of each person?

Identifying the Given

Let J = weight of Julie

T = 2J  ÃƒÂ¢Ã‚†Â weight of Ted

M = 3J  ÃƒÂ¢Ã‚†Â weight of Mike

Total Weight = 210 lbs

J + T + M = 210 ← creating the Formula thru the condition

J + 2J + 3J = 210

5J = 210

J = 42 bls ← Weight of Julie  ÃƒÂ¢Ã‚†Â getting the answer

Applying the Answer to the condition

T = 2J

T = 2(42)

T = 84 lbs  ÃƒÂ¢Ã‚†Â weight of Ted

M = 3J

M = 3(42) = 126 ← weight of Mike

Find four consecutive integers whose sum is 114.

Identifying the Given

4Consecutive intengers

Sum 114

Creating a formula

Let I = integers

I + (I + 1) + (I + 2) + (I + 3) = 114

Solving the formula

4I + 6 = 114

4I = 114 - 6

I = 108/4

I = 27 ← 1st integer

The answer Applying to the condition

I + 1 =  28 ← 2 nd integer

I + 2 =  29 ← 3 rd integer

I + 3 =  30 ← 4 th integer

Hope this helps

Answer 2

1st week = x, 2nd week = x+5, 3rd week = 2x + 10

x+x+5+2x+10 = 431

4x+15 = 431

4x=416

x=104

1st week 104 boxes, 2nd = 109 boxes, 3rd = 218 boxes

Julie = x, Ted = 2x, Mike = 3x

x+2x+3x=210

6x=210

x=35

Julie is 35 pounds, Ted is 70 lbs., Mike is 105 lbs.

x+x+1+x+2+x+3=114

4x + 6=114

4x=108

x=27

27,28,29,30

Answer 3

1.  n= # sold first week

n+(n+5)+2(n+5)=431

n+n+5+2n+10=431

4n+15=431

4n=416

n=104

104, 109, and 218 respectively

2.  n= Julie's weight

n+2n+3n=210

6n=210

n=35

35, 70, and 105 respectively

3.  n= 1st integer

n+(n+1)+(n+2)+(n+3)=114

4n+6=114

4n=108

n=27

27, 28, 29, and 30 respectively