Could you help me with this Algebra problem?

Question

1. Solve the following problem. Show your work.

A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and twenty-one more quarters than dimes. How many coins of each did she return?

Answer 1

let x = nickel, x + 9 = dimes, x + 30 = quarters

.25(x + 30) + .1(x + 9) + .05x = 10

.4x + 8.4 = 10

.4x = 1.6

x = 4

nickel = 4

dime = 13

quarter =34