Could you set up these algebra problems?

Question

1. 3M - N = 2M + N

Solve for M.

2. AX + B = CX + D

Solve for X.

3. 1/2R + 3S = 1

Solve for R.

4. X + K ÷ J = 3/4

Solve for X.

5. 2(U + 3V) = W - 5U

Solve for U.

6. K(Y + 3Z) = 4(Y - 5)

Solve for Y.

7. 2/3F + 5/12G = 1 - FG

Solve for F.

8. A - 3Y ÷ B + 4 = A + Y

Solve for Y.

Answer 1

Yes, thank you.

Answer 2

RETARTED DISCO DONKEY

Answer 3

What does it mean to solve for a variable?

It means to perform operations on an equation

to isolate the variable in question

on one side of the = sign

and all else on the other side

So just do that

one problem @ the time

I'll get you started with three chosen ones

and let you take it from there.

1. 3M - N = 2M + N

Solve for M.

First get all the M terms

on the left side

3M - 2M = 2N

M = 2N ====the answer

5. 2(U + 3V) = W - 5U

Solve for U.

Since U is inside the ()

we have to mult. it out

2U + 6V = W - 5U

7U = W - 6V =====the answer

And one more:

7. 2/3F + 5/12G = 1 - FG

Solve for F.

First get rid of the fractions

by determining the lowest common denominator

of the two which is 12

So mult. all by 12

8F + 5G = 12 - 12FG

Here you have to get the G

out of the 12FG

8F + 12FG + 5G = 12

F(8 + 12G) = 12 - 5G

F = (12 - 5G) / (8 + 12G)

This was a tricky one.

But I hope you can follow

the procedure without

my commentary.

The idea of the whole set of problems

is to get the asked for variable on one side

and all else on the other.

Answer 4

you have to get the like terms together like the nones with N or Y. put all of those on one side of the equal sign. get the Y on one side of the equal sign