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Coulomb's law question!?

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Two identical charges, each –8.00 E-5 C, are separated by a distance of 20.0 cm (100 cm = 1 m). What is the force of repulsion? Coulomb’s constant is 9.00 E9 N*m2/C2

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  1. r=20cm *(1 m/100cm) = 0.2 m

    q=-8.00*10^-5C

    k=9*10^9

    F=K * q^2/r^2

    Your answer: 9 * 10^9 * (-8.00 * 10^-5)^2 / (0.2^2) = 1440N

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