Current from battery, Resistance and Total time before battery dies.?

Question

charge stored is 50 Ah stored in 12 V battery of a car,

4 parkinf bulbs labeled 3.6 W/ 12 V

Now the THREE questions are:

1. Find the current from battery when ONLY 4 parkinf bulbs are switched on.

2. Resistance of 1 bulb.

3. How long it takes for battery to become dead of only parking lights are on

P.S. assume the internal resistance or battery and resistance of connecting wires are negligible.

Answer 1

it depends on how much acide is under the the plastic parts .take one of the pour some water in it.

Answer 2

41-42 hours as you have in the other answers is correct.

But only if the battery is in "like new" shape. A few years old and you will get a lot less. If you had it totally discharged a few times, then a LOT less.  maybe 10 hours.

Answer 3

Assuming the bulbs are wired in parallel...

P=VI

3.6 W = 12V * I

I = 3.6/12 = 0.3 amps * 4 lights = 1.2 amps

V=IR

12V / 0.3 amps = 40 ohms

50 amp-hours in battery, 1.2 amps being used, so:

50 amp-hrs / 1.2 amps = 41.67 hrs until battery is dead

Answer 4

1

3.6w/12v is the current through one lamp. 4 lamps in parallel, multiply this by 4

2

3.6w/12v is the current through one bulb. 12v/i is the resistance.

3

amp hours  divide the number of amps into amp hours to get hours. 1 amp 50 hours 10 amps 5 hours. 100 amps .5 hours.