Definite integral(0,2) te^-t dt?

Question

The e^-t is throwing me off a little. Help me out on this definite integral.

Answer 1

integration by parts:

int(0,2) te^-t dt

= [-te^-t]|(0,2) - int(0,2) -e^-t dt

= -2e^-2 - [e^-t]|(0,2)

= -2e^-2 - (e^-2 - 1)

= -3e^-2 + 1

Answer 2

use integration by parts

hope u know that

-te^-t - integral e^-t

=-te^-t +e^-t     thats the answer now apply limits

Answer 3

integration by parts

u=t  dv= e^-t dt

du =dt v = -e^-t

-te^-t - integral(-e^-t)dt

-te^-t - e^-t

Answer 4

Integrating by parts = -te^-t +Int e^-t dt = -te^-t -e^-t (0,2)=

-2e^-2-e^-2+1 = -3e^-2+1