Question:

Deriving "y" from Aggregate Production Function?

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How do I get the income per capita function from the aggregate prod. function? I need "y" to continue further into my problem..

Here is the info I have...

Assume that the prod. function is Y= K (TO THE 1/2 POWER) L (TO THE 1/2 POWER)

s= .2

depreciation= 0.05

economy starts off w/ k=4

Also...how do you solve for the steady state of y and c?

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2 ANSWERS


  1. Y=(KL)^(1/2)

    Y/L=(KL)^(1/2) / L = (KL)^(1/2) / (L^(1/2))^2

    y=(K/L)^(1/2)

    K/L=k

    y=√k

    Steady-state:

    sy=δk

    0.2√k=0.05k

    4=√k

    k=16

    y=√k=4

    c=y-δk = √k - δk = 4 - 0.05*16 = 3.2

    Current level: k=4

    Steady-state: k=16

    Conclusion: output per worker will increase because per worker capital will increase from 4→16, to increase steady-state output per worker it is required:

    ♦ change production function;

    OR

    ♦ change depreciation (switch to another type of capital)

    OR

    ♦ change saving rate

    Golden rule for given production function:

    y-δk → MAX

    y' - (δk)' = 0

    y' = (δk)'

    1/2√k=δ

    √k=1/2*0.05 = 1/0.1=10

    k*=100

    y*=√k* = 10

    δk=sy

    0.05k=s*√k

    0.05√k=s

    s*=10*0.05=0.5

    c*=y* - δk*=√k* - 0.05k* = 10-5=5


  2. there is two points in your question which are not connected.

    .- Deriving y means to find dy/dL or dy/dK (calculus notation)

    .- Income per capita can be given by y/P (arithmetical notation) where P is population.

    for some economists y<>Y for others y=Y; depends of notation you are using....please precise notation...

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