Describe the effect of a magnetic field on a moving charged particle.

Question

Describe the effect of a magnetic field on a moving charged particle.

Answer 1

there will be a magnetic force exerted on the charged particle.

direction of the force can be resolved using fleming's left hand rule.

Answer 2

F = qvB sin(θ)

where F is the force of magnetic field

where q is the magnitude of the charge of the particle

v its velocity

B is the magnitude of the perpendicular magnetic field

where θ is the angle between the velocity vector and the magnetic field vector. When the vectors are orthogonal to one another θ is equal to 90° and sin θ is 1.

Answer 3

A charged particle moving in a magnetic  field will feel a sideways force that is proportional to the strength of the magnetic field, the component of the velocity that is perpendicular to the magnetic field and the charge of the particle. This force is known as the Lorentz Force. The force is always perpendicular to both the velocity of the particle and the magnetic field that created it. Neither a stationary particle nor one moving in the direction of the magnetic field lines will experience a force. For that reason, charged particles move in a circle (or more generally, helix) around magnetic field lines; this is called cyclotron motion. Because the magnetic field is always perpendicular to the motion, the magnetic fields can do no work on a charged particle; a magnetic field alone cannot speed up or slow down a charged particle. It can and does, however, change the particle's direction, even to the extent that a force applied in one direction can cause the particle to drift in a perpendicular direction.