Determine the volume of a solution with dilution?

Question

Determine the volume of a 0.1505 M Cu(NO3)2 solution necessary to dilute to a final volume of 500.0 mL to make a solution whose final concentration is 200.0 micrograms of Cu2+ per mL.

Answer 1

200.0 mg = 0.200 g

moles Cu2+ = 0.200 g / 63.546 g/mol =0.00315 per mL

moles Cu2+ in 500 mL = 1.57

V = 1.57 / 0.1505 = 10.5 L