Determine whether the lines are parallel,?

Question

determine whether the lines are parallel,

perpendicular, or neither

y = x + 7

y = -x + 2

Answer 1

Perpendicular because the slopes are opposite. slopes are x and as you can see one is x and the other one is -x and their opposites which right away tells that the lines are perpendicular. Perpendicular lines are lines that cross each other in a 90 degree angle.

Answer 2

The equation for a line is y = mx + b, where m = slope. Parallel lines have the same slope. Since the slope in the equations are 1 and -1 respectively, they are not parallel.

Answer 3

These are already in the form of y =mx+b, where m is the slope and b is the y-intercept.

We can see that the slope of the first equation is 1 and the slope of the 2nd equation is -1.  Therefore, the lines are perpendicular (perpendicular lines will have 1 with a slope of x and the other with a slope of -x).  If the lines were parallel, they would have the same slope.

Answer 4

actually they are all wrong.

they are right about the opposite reciprocals though. but if it was perpendicular, it would be: y = -(X/1) + 2

just because it has a negative doesnt make it a reciprical.

the opposite reciprocal of X is -(X/1)

and it isnt parallel because the y-intercepts ( the 7 and 2) are different.

**SO its really NEITHER parallel or perpendicular.**

i hope that helped =]

Answer 5

oh my... looks like the concept of slope is confounding some people

y = x + 7 ==> y = 1x + 7 ==> slope = 1 (not x)

y = -x + 2 ==> y = -1x + 2 ==> slope = -1 (not -x)

the slope is the coefficient of x; that is what you find the negative reciprocal of

-1 / 1 = -1; yes, 1 and -1 are opposite reciprocals

you leave the x alone when you find the opposite reciprocal of the slope

they ARE perpendicular

Answer 6

Neither

y=x+7

x=1,2,3,4,5,6

y=8,9,10,11,12,13  

y=-x+2

x=1,2,3,4,5,6

y=1,0,-1,-2,-3,-4

Plot it and it should be neither

Answer 7

Perpendicular.

The slope is the opposite-reciprocal of the other.  That means perpendicular lines.