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I just want this checked over before I have to mail it in and get it marked. If I'm wrong please tell me why!!Calculate the molarity of the following solutions:1. 250 mL of solution containing 25.0g of NaCL Step 1: Convert to L = 0.25L Step 2: molar mass of NaCl = 58.5 g Step 3: number of moles of NaCl = 4.27 x 10^-1 mol NaCl Step 4: molarity of NaCl= 1.709 M NaCl2. 4.0 L of solution containing 2.8 mol of HNO3 Step 1: Already in L Step 2 and 3: Already in moles Step 4: 0.7 M HNO33. How many grams of CaCL2 are contained in 225 mL of 0.0350 M CaCl2? Step 1: Convert to L = 0.225 L Step 2: Calculate moles = 7.875 x 10^-3 mol CaCl2 Step 3: Molar mass = 111.1 g/mol CaCl2 Step 4: Mass of solute = 0.8749 g CaCl2Thank you for your time!!
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