Did the earth rotation cause an a Centrifugal forces that could really calculated ?

Question

for example is the man who lives in poles (earth rotation less than in middle ) feel the earth attraction more than man who lives in other places ?

Answer 1

yes, the effect of the rotation of the earth to a person standing on the equator requires a  force inwards to keep them moving in a circle, where as the man living on the pole does not have this requirement. this force is provided by the gravitational force, leading to a lower observed force than for a stationary earth. but the man at the pole ends up with a lower gravitational force due to the shape of the earth. because the radius of the earth is lesser a the poles, he receives less gravitational force than the man on the equator, and this outweighs the change due to rotational motion

Answer 2

Heard of gravity?

And, its centripetal force btw.

Answer 3

Actually centrifugal force doesn't exist in nature.

Wikipedia

"A centrifugal force is a particular kind of fictitious force (also known as a pseudo force, inertial force or d'Alembert force), that exists for observers in a rotating reference frame. Unlike real forces such as electromagnetic forces, fictitious forces do not originate from physical interactions between objects."

- smart alec, Doh!

Answer 4

Hope this will help you:

Apparent gravity is weaker at lower latitudes (nearer the equator), for two reasons. The first is that the surface of the Earth is not an inertial frame of reference: a centripetal force is required to keep objects on the surface moving in a circular path around the Earth's axis as the Earth rotates. In providing this centripetal force, some of the gravitational force on an object is "used up" leaving less to contribute to the object's weight. The apparent force due to rotation is called the centrifugal force; on the surface of the Earth, it depends on an object's mass and its latitude (it's zero at the poles and largest at the equator) so it is customarily combined with the Newtonian gravity. Thus, the local gravity, g, is not purely the result of gravitational force, but is actually effective gravity, a combination of true gravity and centrifugal force. It is the effective gravity you measure when you step on a scale or hang a plumb bob. [1]

The second reason is that the Earth's equatorial bulge (itself also caused by centrifugal force) causes objects at the equator to be farther from the planet's centre than objects at the poles. Because the force due to gravitational attraction between two bodies (the Earth and the object being weighed) varies inversely with the square of the distance between them, objects at the equator experience a weaker gravitational pull than objects at the poles.

In combination, the equatorial bulge and the effects of centrifugal force mean that sea-level gravitational acceleration increases from about 9.780 m·s-2 at the equator to about 9.832 m·s-2 at the poles, so an object will weigh about 0.5% more at the poles than at the equator.[2]

The same two factors influence the direction of the effective gravity. Anywhere on Earth away from the equator or poles, effective gravity points not exactly toward the center of the Earth, but rather perpendicular to the surface of the geoid, which, due to the flattened shape of the Earth, is somewhat toward the opposite pole. About half of the deflection is due to centrifugal force, and half because the extra mass around the equator causes a change in the direction of the true gravitational force relative to what it would be on a spherical Earth. (Source: Wikipedia.org)

Answer 5

Yes, he will feel the earth's attraction to be stronger. Part of that is because he is closer to the earth, though.

Whether you call the "centrifugal force" a force is up to you. If you're in a rotating reference frame (such as the earth), it's going to look like a real force, but it only exists because we're not in an inertial reference frame.