Question:

Differential equation question?

by  |  earlier

0 LIKES UnLike

Please someone help.... I'm very lost!!

write the differential equation that fits the physical description.

1. A (spherical) mothball looses volume by evaporation at a rate proportional to its instantaneous area. Hint: you must express the surface area of a sphere in terms of its volume.

2. The velocity at time t of a particle moving along a straight line is proportional to the fourth power of its position x.

I appreciate any help, hints or ideas on how to approach these problems!!

 Tags:

   Report

1 ANSWERS


  1. The volume V of the sphere of radius r is given by

    V = (4/3)πr³

    The surface area A is given by

    A = 4πr²

    The hint says to express A in terms of V. Solve V for r, then put that into the expression for A.

    V = (4/3)πr³

    [3V/(4π)]^(1/3) = r

    A = 4πr² = 4π [3V/(4π)]^(2/3) = (36π)^(1/3) V^(2/3)

    So now,

    dV/dt = kA = k(36π)^(1/3) V^(2/3)

    where k is the proportionality constant.

    2)

    velocity is the derivative of position x with respect to time. So

    dx/dt = kx^4

    where again k is the proportionality constant.

Question Stats

Latest activity: earlier.
This question has 1 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.
Unanswered Questions