Question:

Differentiate (e^3t)ln4t?

by Guest56211  |  earlier

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Differentiate the following equation;

(e^3t)ln4t (e as being log e)

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  1. Product rule is used;

    d/dt ((e^3t)*ln(4t) )

    =[3e^3t * ln(4t)] + [ e^3t * 1/t]

    =[3e^3t * ln(4t)] + [ (e^3t)/t]

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