Dimensional Analysis? Physics!!!!?

Question

Suppose that the displacement of an object is related to time according to the expression x=bt^2. what are the dimensions of B?

Answer 1

x is in units of meters, t is in units of seconds.  So in order to end up with units of meters, you need meters in the numerator and s^2 in the denominator, so it would be m/s^2 (the units of acceleration)

As a side note, Purdue kicks Notre Dames butt =)

Answer 2

displacement is a measure of distance and time is, well time... so:

x[m] = b[?] * (t[s])^2

b[?] = x[m) / (t[s])^2

[?] = [m/s^2]

Answer 3

x=bt^2 ==> b = x / t^2

[b] = [x] / [t^2]

[b] = L / T^2

(dimension of b is: Length above Time squared)