Displacement Vectors...Help Plz...?

Question

As a University student walks to her dorm on the sidewalks, she has three successive displacement vectors (i.e. one right after the other):

ΔrA = (17 m) î

ΔrB = (12 m) ĵ

ΔrC = (13 m) î + (15 m) ĵ

What is the x-component of the total displacement of the student?_________m

What is the y-component of the total displacement of the student? _________m

What is the magnitude of the total displacement of the student? _________m

What is the angle between the displacement vector (i.e. total displacement) and the horizontal axis? _______°

Answer 1

1_  17i +13i =30m

2_ 12j+15j=27m

3_ second root of (30.30 + 27.27) = 40.3m

4_ tan(x)=27/30 x=arctan(27/30)

Answer 2

i=17+13= 30 m

j=12+15= 27 m

magnitude:

sqr(30^2+27^2) = 40.36 m

angle with +x-axis

atn(27/30)*180/3.14159 = @ 41.99 degrees