Question:

Dissociation of Barium Hyrdoxide

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How many ions are formed when 10.5 moles of barium hydroxide dissociates in water?

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  1. The balanced equation is Ba(OH)2 + H2O = BaO + 2H2 + O2.  The ratio of all ingredients is in the equation is 1:1:1:2:1.  If 1 is represented by 10.5 moles, there would be 10.5 moles of Ba(OH)2, 10.5 moles of H2O, 10.5 moles of BaO, 21 moles of H2 and 10.5 moles of O2.


  2. To answer the question, first determine the chemical formula of Barium hydroxide:

    Ba(OH)2

    next, write a balanced equation describing its dissassociation into ions:

    Ba(OH)2 -> Ba(+2) + 2OH(-)

    The equation indicates three ions are formed for every molecule of Ba(OH)2. Therefore, three times the number of moles of Ba(OH)2 molecules are the number of ions.


  3. Barium hydroxide is known to be a strong base which means that what does dissolve will dissociate completely.   If a mole of Ba(OH)2 dissociates, then 3 moles of ions are produced.

    If (if there is sufficient water) 10.5 moles of Ba(OH)2 dissociates then 31.5 moles of ions will be produced.

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