Distance, velocity, acceleration?

Question

A train is traveling down a straight track at 33 m/s when the engineer applies the brakes, resulting in an acceleration of -1.0 m/s^2 as long as the train is in motion. How far does the train move during a 26 s time interval starting at the instant the brakes are applied?

Answer 1

How far does the train move during a 26 s

(33*26)+(1/2)*(-1)*26^2 = 520m

Answer 2

s = u t + 0.5 a t^2

Where s is the distance travelled (strictly speaking, the displacement)

Where u is the original velocity

Where a is the acceleration or deceleration

Where t is the time passed

Therefore:

s = 33 x 26 + 0.5 x -1 x 26 x 26

s = 520m