Distance and force relationship?

Question

I need help answering this question. If somebody could show me the steps, it would be greatly appreciated.

Two charges attract each other with a force of 1.2 N. What will be the force if the distance between the two is reduced to 1/9 the original volume?

I know that the force will be greater, but I'm not sure how to find out the exact value of that force.

Answer 1

The charges being the same, the eletrostatic force is inversely proportional to the square of their distance.

F2 / F1 = (d1 / d2)^2

F2 = F1 (d1 / d2)^2

Since d1 = 9 d2

F2 = 81 F1

F2 = 81 * 1.2 N

F2 = 97.2 N

Answer 2

If both elements attract each other then the force your looking for has no value. To capture negative energy is to capture a black hole.