Distance between 2 points with 3 coordinates?

Question

What is the distance in space between the points with coordinates

(-3, 6, 7) and (2, -1, 4)

Answer 1

The distance formula for two points in space is almost the same as the 2d formula.

sq rt((x1-x2)^2+(y1-y2)^2+(z1-z2)^2)

sq rt(5^2+7^2+3^2)

sq rt(25+49+9)

sq rt(83)

Your final answer is the square root of 83

Answer 2

Have to use Distance Formula derived from Pythagorean Theorem:

Distance = sqroot[(x2-x1)^2+(y2-y1)^2+(z2-z1)^2]

Answer 3

d = sqrt( (-3 - 2)^2 + (6 + 1)^2 + (7 - 4)^2) = sqrt ((-5)^2 + 7^2 + 3^2) =

= sqrt (25 + 49 + 9) = sqrt (83)

Answer 4

Same as with 2 coordinates

d² = (x1-x2)² + (y1-y2)² + (z1-z2)²

d² = (-3-2)² + (6- -1)² + (7-4)²

d² = 25 + 49 + 9

d² = 83

d = sqrt(83) = 9.11

Answer 5

d = sqrt[(2 - (-3))^2 + (-1 - 6)^2 + (4 - 7)^2]

= sqrt[(5)^2 + (-7)^2 + (-3)^2]

= sqrt[25 + 49 + 9]

= sqrt[83]

= 9.11

Answer 6

distance = Sqroot((x2 - x1)^2+(y2 - y1)^2+(z2 - z1)^2)

so sqroot((2 + -3)^2 + (-1 - 6)^2 + (4 - 7)^2)

sqroot(5^2 + -5^2 + 3^2)

sqroot(25 + 25 +9)

sqroot(59)

Which is around 7.681145748

Teacher would probably like it if you left it at sqroot(59)