Problem: A car traveling 55 km/h slows down at a constant 0.50 m/s^2. Calculate (a) the distance the car coasts before it stops, (b) the time it takes to stop, and (c) the distance it travels during the first and fifth seconds.
v(initial) = velocity(initial) = 55km/h = 15.28m/s
v = velocity
a = acceleration = -0.50m/s^2
For (a), I used the equation v^2 = v(initial)^2 + 2a(x - x(initial)) to get the resulting displacement of 230 meters.
For (b), I found the time using the equation v = v(initial) + at, which resulted in 31 seconds.
However, I really have no idea how to approach (c). Any help would be greatly appreciated.
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