Question:

Distance=rate(time) help please!!!!!!!!!!!?

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For vacation tom drove to a beach that was 300 miles away from his home. He made a reststop when he was two thirds of the way there.

It took him 4 hours to get to a reststop. In miles per hour what was the average speed that he drove for the first hours of the trip?

Thank you!!

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5 ANSWERS


  1. 2/3 of trip is 200 miles.

    200=rate (4)

    200 divided by 4 = rate (speed)

    50mph = speed for first part of trip

    the remaining 100 miles is at 25mph

    100 divided by 25 = 4 hours

    the total trip took him 8 hours plus the time he was at the rest stop


  2. 50 mph

  3. Speed = distance/time

    Total distance = 300 miles

    time to reststop = 4 hours

    distance to reststop = 300 miles * 2/3 = 200 miles

    speed to reststop = 200 miles / 4 hours = 50 miles per hour

    time to beach

    speed restriction = 25 miles per hour

    distance remaining = 300 miles - 200 miles = 100 miles

    time remaining = 100 miles / 25 miles per hour = 4 hours

    total time = 8 hours

    average speed = total distance / total time

    average speed = 300 miles / 8 hours = 37.5 miles per hour

  4. it would take him another 4hrs since 4*25 = 100, and 100 + 200 = the total 300

  5. 50 mph

    because it was 200 miles to the rest stop and it took 4 hours so 200 divided by 4 is 50.

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