Distributive property to expanded form...?

Question

Use the Distributive property to write the expanded form of

2(x^2-x)

Use the Distributive property to write the factored form of

2x^3+4x^2

i need help of how to solve them not just the answer..thanks

Answer 1

distributive property says this:

a(b + c) = ab + bc

you are "distributing" the number on the outside to each term inside the parentheses. so...

2(x^2 - x) = 2x^2 - 2x    the 2 on the outside gets multiplied by each term inside.

the 2nd problem is the opposite. You have to pull out a common term. The common factor is 2x^2. so...

2x^2(x + 2)

to check, just DISTRIBUTE the 2x^2 back in and see if you get the original problem

Answer 2

The distributive property says that if you multiply something by a parenthesis item, it's the same as multiplying it by each thing in the parentheses.

So 2(x^2 - x) = 2*x^2 - 2*x, which you can simplify further on your own.

In reverse the distributive property says that if you have an item multiplied by several things you can take it out.

Here's an example: 6+4*x, both 6 and 4 have a 2 in them.  So you can rewrite this as 2*(3+2*x).

In your case, there is a 2x^2 in both.

So you rewrite is as 2x^2(x + 2)!

Answer 3

2x(x-1)

2x^2(x+2)

You get these by dividing each inner term by what they have in common.  Put the common divisor outside the parentheses and what's left over remains inside.

Answer 4

well, you multiply the 2 into both parts of what is in parentheses. so 2(x^2-x)=2(x^2)-2x.

with the second, you want to look for something every term has in common.

both 2x^3 and 4x^2 are divisible by 2, and by x^2, so put that out in front and divide it out of the original expression.

it should look like: 2x^2(x+2)